SOLUTION: OK this is a really confusing question for me i may be haveing problems with a question because i am missing certian things that i need to understand first. oh well please help me.

Question 4449: OK this is a really confusing question for me i may be haveing problems with a question because i am missing certian things that i need to understand first. oh well please help me. If a hoop has an area of 25*3.14 and to jump through it a dog must have 2 inches less diameter then what is the largest the dog can get with out endangering the act
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
A hoop is circular. The area of a circle is given by: A = (pi)r^2 or if you use the diameter, d, of the circle, then it's: A = (pi)(d/2)^2 = (pi)(d^2)/4
So, you are given the area of the hoop (circle): A = 25(pi) and you need to find the diameter of this hoop (circle).
A = (pi)(d^2)/4 = 25(pi) Divide both sides bi pi
(d^2)/4 = 25 Multiply both sides by 4.
d^2 = 100 Take the square root of both sides.

d = 10 inches.
In order for the dog to fit the requirements of the job, it must be at least 2 inches smaller in diameter than the diameter of the hoop (10 inches) which means the dog has to have a diameter of 8 inches or less.
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