SOLUTION: Prove that the graph of any equation of the form y=ax^2+bx+c has exactly one y-intercept.

Question 421878: Prove that the graph of any equation of the form y=ax^2+bx+c has exactly one y-intercept.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the equation is y = ax^2 + bx + c

the y intercept is the value of y when the value of x is 0.

when the value of x is 0, this equation becomes y = a*0 + b*0 + c which becomes y = c

there is only 1 value of c that can satisfy this equation, and that is the value of c that is given at the start of the equation.

example:

y = 20x^2 + 30x + 15

when x = 0, this becomes y = 20*0 + 30*0 + 15 which reduces to y = 15.

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