Hi

Find the equation of the circle that has its center at (6,-5) and passes through (1,7).

(6,-5)

(1,7)

 r = sqrt(5^2 + (-12)^2) = 13      |D = 

Standard Form of an Equation of a Circle is 

where Pt(h,k) is the center and r is the radius



   (x-6)^2 + (y+5)^2 = 169



 

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