Hi

circle whose diameter has endpoints of (3, 0) and (7, 10)

(3, 0) and 

(7, 10) Midpoint is   (5,5)             |  ( , )

(3, 0) and 

(7, 10  D = sqrt( (-4)^2 + (-10)^2))        |  D =  

  D = sqrt(116) = 2sqrt(29) and r = sqrt(29)

 Standard Form of an Equation of a Circle is 



where Pt(h,k) is the center and r is the radius

   (x-5)^2 + (y-5)^2 = 29





   

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