SOLUTION: The pool at a park is circular. You want to find the equation of the circle that is the boundary of the pool. Find the equation if the area of the pool is 800 sq. feet and (0, 0) r

Algebra ->  Circles -> SOLUTION: The pool at a park is circular. You want to find the equation of the circle that is the boundary of the pool. Find the equation if the area of the pool is 800 sq. feet and (0, 0) r      Log On


   

Question 399984: The pool at a park is circular. You want to find the equation of the circle that is the boundary of the pool. Find the equation if the area of the pool is 800 sq. feet and (0, 0) represents the center of the pool.
A. x^2 + y^2 -800 = pie
B. x^2 + y^2 =800/pie
C. x^2 + y^2 = 800
D. x^2 + y^2 = pie/800
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The pool at a park is circular. You want to find the equation of the circle that is the boundary of the pool. Find the equation if the area of the pool is 800 sq. feet and (0, 0) represents the center of the pool.
A. x^2 + y^2 -800 = pie
B. x^2 + y^2 =800/pie
C. x^2 + y^2 = 800
D. x^2 + y^2 = pie/800
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Area+=+pi%2Ar%5E2
r%5E2+=+%28800%2Fpi%29
--> B x%5E2+%2B+y%5E2+=+800%2Fpi
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PS It's pi, the Greek letter, not pie, the dessert.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

 A = pi%2Ar%5E2=+800

pi%2Ar%5E2=+800

r%5E2=+800%2Fpi

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

where Pt(h,k) is the center and r is the radius

 (0, 0) represents the center of the pool. 

 x^2 + y^2 = r^2

 x^2 + y^2 = 800%2Fpi