SOLUTION: Find the radius of a circle defined by the equation: x^2+y^2+12x+6y+29=0.
-> SOLUTION: Find the radius of a circle defined by the equation: x^2+y^2+12x+6y+29=0.
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Geometry: Circles and their properties
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Find the radius of a circle defined by the equation: x^2+y^2+12x+6y+29=0.
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is the equation of a circle centered at
Take your standard form equation and complete the square on each of the variables.
First move the constant to the RHS and group like variables:
Take the coefficient on the first degree
term, divide by two, square the result, and add the squared result to both sides. Do the same thing with the
Factor the two perfect square trinomials and collect terms in the RHS:
From which you can determine the center by inspection and the radius by taking the positive square root of the RHS.
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