Hi,         

Standard Form of an Equation of a Circle is 

where Pt(h,k) is the center and r is the radius

4x^2+4y^2-24x-48y-16 = 0

x^2+y^2-6x-12y-4 = 0

completing the squares to put into standard form

 (x-3)^2 - 9 + (y-6)^2 - 36 - 4 = 0

  (x-3)^2 + (y-6)^2 = 49

Center Pt(3,6) radius = 7

CIRCLE



 

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