Hi

Standard Form of an Equation of a Circle is 

where Pt(h,k) is the center

x^2+y^2-10x+12y+12=0

completing the squares to put into the Standard Form

x^2 -10x + y^2 +12y + 12 = 0

 (x-5)^2 - 25 + (y+6)^2 - 36 + 12 = 0

  (x-5)^2 + (y+6)^2 -49 = 0

  (x-5)^2 + (y+6)^2 = 49 

Center (5,-6)  radius = 7

 

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