SOLUTION: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0.

SOLUTION: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0.

Algebra.Com

Question 383021: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0.
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
3x^2+3y^2+12x-12x-48=0=>x^2+y^2=16 => radius is 4.
RELATED QUESTIONS
find the radius of the circle defined by the equation:... (answered by scott8148)

find the radius of the circle defined by the equation:... (answered by Fombitz,ewatrrr)

Find the radius of a circle defined by the equation:... (answered by solver91311)

Find the radius of the circle defined by the equation x^2+y^2+12x+8y+16=0 Is kinda... (answered by ewatrrr)

Find the center of a circle defined by the equation :... (answered by Fombitz)

A circle is defined by the following equation : 3x^2+3y^2-24x+42y+183=0... (answered by funmath)

A circle is Defined by the following equation, 3x^2+3y^2-30x+27=0. what is the... (answered by htmentor)

-3x^2 - 3y^2 + 12x + 96=0 a. find the center b. find the... (answered by ewatrrr)

Find the length of the radius of a circle whose equation is 2x^2+2y^2-12x+4y-15=0 (answered by Fombitz)