SOLUTION: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0

SOLUTION: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0

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Question 382993: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
dividing by 3 and adding 16___ x^2 + y^2 + 4x - 4y = 16

completing the squares ___ x^2 + 4x + 4 + y^2 - 4y + 4 = 16 + 4 + 4

(x + 2)^2 + (y - 2)^2 = 24

r = sqrt(24) = 2 sqrt(6)
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