SOLUTION: I need help to find the x and y intercepts of these circles. Circle 1 (x+2)^2+(y+3)^2=4 and Circle 2 x^2+y^2-18x-2y+66=0. Thanks in advance!!!!

Question 380874: I need help to find the x and y intercepts of these circles. Circle 1 (x+2)^2+(y+3)^2=4 and Circle 2 x^2+y^2-18x-2y+66=0.
Thanks in advance!!!!
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Circle 1: Letting y = 0 to solve for the x-int, we get . This equation has no solution, hence there are no x-intercepts.
Letting x = 0 to find the y-int, we get. The only solution is y =-3.Thus the y-intercept is (0,-3).
Circle 2: Let y = 0 to find the x-int. Then . The solutions to this are . These are also the x-intercepts.
Let x = 0 to find the y-int. Then . This equation has no real roots. Therefore there are no y-intercepts.
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