SOLUTION: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.

SOLUTION: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.

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Question 372724: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square in and .

Compare to the general equation for a circle centered at (,) with a radius :

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