SOLUTION: find the radius of the circle defined by the equation: x^2+y^2+12x+4y+76=0.

Question 372701: find the radius of the circle defined by the equation: x^2+y^2+12x+4y+76=0.
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square in and .

Compare this equation to the general equation of a circle centered at (h,k) with a radius R.

In this case, your equation is not the equation for a circle.

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
The standard equation of a circle with center C(h,k) and radius r is :

Find the radius
x^2+y^2+12x+4y+76=0
completing the squares
x^2+12x + y^2+4y + 76=0
(x+6)^2 + (y+2)^2 -36 -4 + 76 = 0
(x+6)^2 + (y+2)^2 = 36 = 6^2
radius = 6, center (-6,-2)

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