SOLUTION: Find the radius of a circle defined by the equation 6x^2+6y^2+48x+108y+558=0 They want you put it in this form (x-h)^2+(y-k)^2=r^2 I first Subtracted the 558 on both sides but I

Question 372491: Find the radius of a circle defined by the equation 6x^2+6y^2+48x+108y+558=0
They want you put it in this form (x-h)^2+(y-k)^2=r^2
I first Subtracted the 558 on both sides but I got stuck after that
Here's what I have
6x^2+6y^2+48x+108y+558-558=0-558
6x^2+6y^2+48x+108y=558
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
You need to complete the square in and .

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Center:(,)
Radius:

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