SOLUTION: : Factor completely:
3w^2 + 27w + 54
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Question 368992: : Factor completely:
3w^2 + 27w + 54
Found 2 solutions by Fombitz, lefty4ever26:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Answer by lefty4ever26(59) (Show Source): You can put this solution on YOUR website!
First you factor out the number that all three have in common which in this case is 3. SO we get:
3(w^2+9w+18)
Then you need to find the two numbers that multiply together to equal 18 and add together to equal 9. That would be 6 and 3 because 6*3=18, 6+3=9
So we get:
3(w+6)(w+3)
This is fully factored. To check you answer you would use the FOIL method to multiply the (w+6)(w+3). Then you would multiply the 3 back into that answer.
Hope this helps!
**UPDATED CHECK**
3(w+6)(w+3) FOIL is First Outside Inside Last
3(w^2+3w+6w+18)
3(w^2+9w+18) Then distribute the 3 through by multiplying
3w^2+27w+54
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