SOLUTION: Show that the equation represents a circle, and find the center and radius of the circle.
2X^2 + 2Y^2 - 3X = 0
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Question 310855: Show that the equation represents a circle, and find the center and radius of the circle.
2X^2 + 2Y^2 - 3X = 0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You know that the equation represents a circle because the coefficients on the squared variables are equal.
To find the center, complete the square. Since there is no first degree y term, the square is already complete on y, hence the y coordinate of the center is zero.
Divide the equation by the coefficient on x.
Divide the coefficient on the first degree x term by 2, then square the result. Add that result to both sides of the equation.
Factor the perfect square trinomial in x:
^2\ +\ y^2\ =\ \left(\frac{3}{4}\right)^2)
The center is at )
and the radius is 
John
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