SOLUTION: What is the radius and the center for a circle with the following equation:
(x+4)^2+y^2=37
Algebra.Com
Question 308766: What is the radius and the center for a circle with the following equation:
(x+4)^2+y^2=37
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the radius and the center for a circle with the following equation:
(x+4)^2+y^2=37
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Form: (x-h)^2 + (y-k)^2 = r^2
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Center: (-4,0)
Radius: sqrt(37)
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Cheers,
Stan H.
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