SOLUTION: i need to graph {{{2x^2+2y^2=18}}} heres a link if u need to see options http://www2.edmastery.com/files/nnds_prod_data/itemAssets/NN%2EMAT%2E301307%2E2%2EHO%5Cres00006%5Cc52d8

Question 284792: i need to graph
heres a link if u need to see options
http://www2.edmastery.com/files/nnds_prod_data/itemAssets/NN%2EMAT%2E301307%2E2%2EHO%5Cres00006%5Cc52d8583b1b74391be173b8505733054%5C27%2EJPG
Found 3 solutions by stanbon, richwmiller, toidayma:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
i need to graph 2x^2+2y^2 = 18
---
Divide thru by 2 to get:
x^2 + y^2 = 9
----------------------------
The graph is a circle with center at (0,0)
with radius = 3.
=========================
Cheers,
Stan H.
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
x^2+y^2=9
center is at 0,0 and the radius is 3
let x=0 find y
let y=0 find x

Answer by toidayma(44)   (Show Source): You can put this solution on YOUR website!
This kind of equations, i.e. (x - a)^2 + (y - b)^2 = R^2 is a equation of a circle and its center is at (a,b) and the radius is R.
In your equation, 2x^2 + 2y^2 = 18 <-> x^2 + y^2 = 9 <-> (x-0)^2 + (y-0)^2 = 3^2
Therefore, it is a circle with its center at (0,0) and the radius length is 3.
So you know why it is C, right?
By the way, if the coefficients of x^2 and y^2 are equals (i.e. you always have the equations look like this: k(x-a)^2 + k(x-b)^2 = k*R^2 (k<>0), you can be sure that its graph is a circle, but when the coefficients are not equal, you have a graph of an ellipse.
Good luck.
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