SOLUTION: I have an equation for a circle (x+3)^2+(y-1)^2=25 where the centre point is 3,1 and th radius is 5. I need to show that the line of equation y=-x-1 intercepts the circle. I have s

Question 28302: I have an equation for a circle (x+3)^2+(y-1)^2=25 where the centre point is 3,1 and th radius is 5. I need to show that the line of equation y=-x-1 intercepts the circle. I have substituted the value of y into the circle
(x+3)^2+(-x-1-1)^2=25
(x+3)^2+(-x-2)^2=25
But how do i get from here to 2x^2+10x-12=0 an then show that the line intercepts?
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
is fine so far. And where do you get from? How do you know that is the quadratic you are aiming for? :-)

Anyway,

(x+6)(x-1) = 0

so x+6=0 OR x-1=0
--> x=-6 OR x=1

This says there are 2 solutions of the "circle" and the "line" ie where they are EQUAL ie where they intersect.

I have told you their x-coordinates. If you need to quote the y values....find them too, from y=-x-1... easiest equation to use.

jon.

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