SOLUTION: Find the equation of the circle that has its center at (1,2) and that passes through the origin.
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Question 272560: Find the equation of the circle that has its center at (1,2) and that passes through the origin.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the equation of the circle that has its center at (1,2) and that passes through the origin.
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The radius is the distance from the center to the origin.
r^2 = 1^2 + 2^2 = 5
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(x-1)^2 + (y-2)^2 = 5
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