SOLUTION: the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line. please may you explain how you get to the answer aswel

Algebra ->  Circles -> SOLUTION: the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line. please may you explain how you get to the answer aswel      Log On


   

Question 264535: the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line. please may you explain how you get to the answer aswell, thankyou!
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line.
---------------
The line crosses the x-axis at y= 0, --> (4,0).
The line crosses the y-axis at x-0, --> (0,-8)
Those are the 2 points.
-----------------
The midpoint is the center of the circle.
To find the midpoint, get the average of x and y separately.
x: (0+4)/2 = 2
y: (0-8)/2 = -4
--> M (2,-4)
----------
The distance from M to A or B is the radius.
r%5E2+=+diffy%5E2+%2B+diffx%5E2
r%5E2+=+2%5E2+%2B+4%5E2+=+20
--------------------
--> %28x-2%29%5E2+%2B+%28y%2B4%29%5E2+=+20