SOLUTION: The ordered pair (-3,2) lies on a circle with center (0,3). What is the equation of the circle? i dont get how to work this problem out can i please get help?

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Question 258586: The ordered pair (-3,2) lies on a circle with center (0,3). What is the equation of the circle? i dont get how to work this problem out can i please get help?
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The ordered pair (-3,2) lies on a circle with center (0,3). What is the equation of the circle? i dont get how to work this problem out can i please get help?
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The distance from the point to the center is the radius. Find the distance.
r^2 = diffy^2 + diffx^2
r^2 = 1 + 9 = 10
The distance squared is ok.
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The eqn for a circle of radius r, with its center at (h,k) is:
(x-h)^2 + (y-k)^2 = r^2
--> x^2 + (y-3)^2 = 10

Answer by Edwin McCravy(20086)   (Show Source): You can put this solution on YOUR website!
The ordered pair (-3,2) lies on a circle with center (0,3). What is the equation of the circle? i dont get how to work this problem out can i please get help?

Momorize these two facts:

1.  The equation of the circle with center (h,k) and radius, r, is:

(x-h)2 + (y-k)2 = r2

2. The distance, d, between the points (x1,y1) and
   (x2,y2) is given by this formula:

  

Plot those points:



Now if we connect them that will be a radius, and we can draw the circle
by putting the point of a compass on (0,3) and the pencil of the compass
on (-3,2) and swinging it around.



If we find the distance between those two points we will have the radius r.

So we use this formula to find that distance:

 

where (x1,y1) = (0,3) and (x2,y2) = (-3,2)

Substituting:



 





So d is the radius r.

Now we are ready to substitute into

 with center  and  .





Edwin

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