SOLUTION: Please help!!! I'll try to explain this well enough to understand since I cannot c&p the figure. But if possible... Please explain!!!Thanks so much=) I need to find the area of

Algebra ->  Circles -> SOLUTION: Please help!!! I'll try to explain this well enough to understand since I cannot c&p the figure. But if possible... Please explain!!!Thanks so much=) I need to find the area of       Log On


   

Question 254593: Please help!!! I'll try to explain this well enough to understand since I cannot c&p the figure. But if possible... Please explain!!!Thanks so much=)
I need to find the area of a figure shaped like an ice cream cone. The top (semicircle) is 6m. The figure shows an arc in the semicircle (I'm not real sure about the importance of that). And the bottom of the "cone" is 8m.
If you can make sense of this, I would greatly appreciate any help!!!!!
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
I will give it a shot.
There is an ice cream sphere in an ice cream cone. The semi-circumference of the sphere is 6m. That means that the circumference is 12m.
The circumference formula is
2%2Api%2Ar+=+12
So, r = 6/pi.
I assume the height of the cone is 8m.
I guess you are to find the volume of the object.
There are 2 volumes we have to find . . .
(1) the cone and
(2) 1/2 sphere of ice cream.
--
The cone volume is
V+=+%281%2F3%29Bh
area of base, B, is
B+=+pi%2Ar%5E2
or
pi%2A%286%2Fpi%29%5E2+=+36%2Fpi
Volume+=+%281%2F3%29%2836%2Fpi%29%288%29 = 96%2Fpi
--
Ice cream volume is 1/2 sphere so,
V+=+%281%2F2%29%284%2F3%29%2Api%2Ar%5E3
V+=+%282%2F3%29%2Api%2A%286%2Fpi%29%5E3
V+=+%282%2F3%29%2Api%2A%28216%2Fpi%5E3%29
V+=+144%2Fpi%5E2
So the sum of volumes appears to be
V+cone+%2B+V+sphere+=+96%2Fpi+%2B+144%2Fpi%5E2
V+cone+%2B+V+sphere+=+%2896pi+%2B+144%29%2Fpi%5E2