SOLUTION: write the equasion of a circle with a diameter having endpoints at
(-2,6) and (8,4)?
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Question 142451: write the equasion of a circle with a diameter having endpoints at
(-2,6) and (8,4)?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the center is midway between the endpoints at (3,5)
the radius squared is the square of the distance from the center to an endpoint
__ r^2=5^2+1^1
(x-3)^2+(y-5)^2=26
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