SOLUTION: circle with equation: X^2 + Y^2 - 6X - 18Y + 45 Tangent touches the circle at point T equation of the tangent is 2Y = X Show algebraically that T has coordinates (6,3).

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Question 141508: circle with equation: X^2 + Y^2 - 6X - 18Y + 45
Tangent touches the circle at point T equation of the tangent is 2Y = X
Show algebraically that T has coordinates (6,3).

Answer by Edwin McCravy(20086)   (Show Source): You can put this solution on YOUR website!
circle with equation:
Tangent touches the circle at point T equation of the tangent is
Show algebraically that T has coordinates (6,3).

Just solve the system




by substitution

Substitute 2Y for X in the first:










Divide every term by 5



Factor:

(Y-3)(Y-3)=0

 gives 
 gives 

[The fact that we get only one solution tells us
that the line touches the circle in only one
point. So this proves that it is indeed tangent]

Now to find 

Substitute  for  in




6=X

So the point of tangency is (6,3)

Edwin

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