SOLUTION: A circle whose equation is (x+5)^2+(y+3)^2=36 is stretched by a factor of 1/4. What is the new equation? I think the answer is (x+5)^2+(y+3)^2=9/4. Can someone PLEASE help me??
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-> SOLUTION: A circle whose equation is (x+5)^2+(y+3)^2=36 is stretched by a factor of 1/4. What is the new equation? I think the answer is (x+5)^2+(y+3)^2=9/4. Can someone PLEASE help me??
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Question 139829: A circle whose equation is (x+5)^2+(y+3)^2=36 is stretched by a factor of 1/4. What is the new equation? I think the answer is (x+5)^2+(y+3)^2=9/4. Can someone PLEASE help me?? Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! I would say that if the circle is increased by a factor of 1/4, then it is NOW a radius of 6 PLUS 1/4 of 6. This would be 6 + 3/2, which would be 15/2. So this makes , and the equation would be . I'm not sure how you arrived at 9/4 in your equation, but the circle must be STRETCHED, so now the larger r^2 must be LARGER than 36. Do you see what I am saying??
