You can put this solution on YOUR website! Find the equation of tangents to
x^2+y^2-6x-2y+9=0
through the origin.
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Take the derivative to get:
2x+2yy'-6-2y'=0
y'(2y-2) = (6-2x)
y' = (6-2x)/(2y-2)
y'(0,0) = 6/-2 = -3
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Equation of the tangent at (0,0) is y = -3x
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Cheers,
Stan H.
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