SOLUTION: Find the equation of tangents to x^2+y^2-6x-2y+9=0 through the origion.

Question 138626: Find the equation of tangents to
x^2+y^2-6x-2y+9=0
through the origion.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of tangents to
x^2+y^2-6x-2y+9=0
through the origin.
-------------------------
Take the derivative to get:
2x+2yy'-6-2y'=0
y'(2y-2) = (6-2x)
y' = (6-2x)/(2y-2)
y'(0,0) = 6/-2 = -3
--------------------------
Equation of the tangent at (0,0) is y = -3x
==========================
Cheers,
Stan H.

RELATED QUESTIONS
find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y (answered by Alan3354)

find the equation of the tangents and normal to curve y^2+8x=0, parallel to... (answered by Alan3354)

Please help me solve this equation: Find equations of the tangents to the curve {{{ x =... (answered by Jk22)

find the equation of the tangents and normal to curve x^2 - y^2 = 15, parallel to 4x - (answered by Alan3354)

Find the equation of all tangents to the circle x^2 + y^2 - 2x + 8y - 23 = 0 a) having... (answered by Alan3354)

If y= mx + c is a tangents to the circle x^2 + y^2 =r^2,show that c = rsqrt(1 + m^2}}}.... (answered by anand429)

can you please help me solve these problems on parabolas and circles? Thanks 1.Find the... (answered by lwsshak3)

can you please help me solve this problem on hyperbola? Thanks 1.find the equation of... (answered by lwsshak3)

the circle C:x^2+y^2-2gx+2fy+e=0 has its center in the quadrant. the x and y axes are... (answered by Fombitz)