SOLUTION: Picture- Quadrilateral ABCD inscribed in a circle. If {{{m<D=75}}}, measure arc {{{AB = x^2}}}, measure arc {{{BC = 5x}}}, and measure arc {{{CD= 6x}}}, find x and {{{m<A}}}
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Question 1190631: Picture- Quadrilateral ABCD inscribed in a circle. If , measure arc , measure arc , and measure arc , find x and
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
Here's one way to draw out the starting diagram

I used GeoGebra to make the diagram.
Plot point E at the center of the circle.
Draw segments EA and EC to form angle AEC.
By the inscribed angle theorem, the inscribed angle D = 75 is exactly half of the central angle AEC because both subtend the same arc ABC.
This means angle AEC = 2*(inscribed angle D) = 2*75 = 150 degrees.
This further means that arc ABC is also 150 degrees.
The arc pieces AB = x^2 and BC = 5x add up to this 150 degree measure
(arc AB) + (arc BC) = arc ABC
x^2+5x = 150
x^2+5x-150 = 0
Use the quadratic formula to solve for x
Use a = 1, b = 5, c = -150
or
or
or
We'll ignore the negative x value because we cannot have negative angle measures.
Arc AB = x^2 = 10^2 = 100
Arc BC = 5x = 5*10 = 50
(arc AB) + (arc BC) = arc ABC
(100) + (50) = 150
150 = 150
So the x value checks out.
Now notice that inscribed angle A subtends the arc BCD
arc BCD = (arc BC) + (arc CD)
arc BCD = (5x) + (6x)
arc BCD = 11x
arc BCD = 11*10
arc BCD = 110 degrees
We cut that in half to find inscribed angle A (refer to the inscribed angle theorem)
angle A = (arc BCD)/2
angle A = (110)/2
angle A = 55 degrees
-----------------------------------
Answer:
x = 10
Angle A = 55 degrees
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