SOLUTION: Mr. Nim designed an arch for the top of his main gate. The arch will be made out of bent iron. In the design, the 20 segments between the two concentric semicircles are each 0.5 me
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Question 1174264: Mr. Nim designed an arch for the top of his main gate. The arch will be made out of bent iron. In the design, the 20 segments between the two concentric semicircles are each 0.5 meter long. Suppose the diameter of the outer semicircle is 10 meters. What is the length, in whole meters, of the shortest iron needed to make the arc?
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
The diameter of the outer semicircle is 10m, and the segments between the two semicircles are each 0.5m long, so the diameter of the inner semicircle is 9m.
outer semicircle diameter 10m --> arc length 5pi meters
inner semicircle diameter 9m --> arc length 4.5pi meters
20 segments each 0.5m long --> 10m
ANSWER: Total length of iron required: (10+9.5pi) meters
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