SOLUTION: What is the equation in standard form of the circle whose center is at (2,8) and passes through the origin?

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Question 1169733: What is the equation in standard form of the circle whose center is at (2,8) and passes through the origin?
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

It is


     +  = ,


which is the same as


     +  = 68.



Notice that the right side is the square of the radius,

and the radius in this case is the distance of the given point from the origin of the coordinate system.

Solved.


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By the way,  the circle is shown  INCORRECTLY  in the post by  @MathLover1.

Would it be plotted correctly,  the circle must go through the point  (4,0),  too.



Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

the equation in standard form of the circle:

given: center is at (,)=(,)


given: passes through the origin:(,)
use it to calculate radius




and your formula is:



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