SOLUTION: 3x^2 +18x+3y^2=0 Solve for center, radius and x,y intercepts.

Question 1164378: 3x^2 +18x+3y^2=0
Solve for center, radius and x,y intercepts.
Answer by ikleyn(52818) (Show Source): You can put this solution on YOUR website!
.


The given equation is EQUIVALENT to

     = 0


(after dividing both sides by 3).



Next, the last equation you transform using "completing the square"

     +  = 

     +  = .



It describes the circle of the radius 3 centered at the point  (-3,0).

Solved, answered and explained.

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