SOLUTION: Which is the equation of a circle that passes through (2.2) and is centered at (5.6) Answers: A. (x-6)^2 + (y-5)^2=25 B. (x-5)^2 + (y-6)^2=5 C. (x+5)^2 + (y+6)^2=25 D. (x-5)

Question 1159152: Which is the equation of a circle that passes through (2.2) and is centered at (5.6)
Answers:
A. (x-6)^2 + (y-5)^2=25
B. (x-5)^2 + (y-6)^2=5
C. (x+5)^2 + (y+6)^2=25
D. (x-5)^2 + (y-6)^2=25
Thank you for doing this during quarantine :)
Found 3 solutions by Alan3354, MathLover1, MathTherapy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Which is the equation of a circle that passes through (2.2) and is centered at (5.6)
-------------
Use commas for the points.
---
Which is the equation of a circle that passes through (2,2) and is centered at (5,6)
Find the distance between the 2 points.
That's the radius of the circle.
==========
is a circle, where (h,k) is the center.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Which is the equation of a circle that passes through (,) and is centered at (,)

recall: the equation of a circle is where and are coordinates of the center and is radius

Answers:
A. =>, -> not your answer
B. =>, -> might be your answer
check if this a circle that passes through (,)

=> a circle does not passes through (,)
so, B. is not your answer either

C. =>, -> not your answer

D. =>, -> might be your answer
check if this a circle that passes through (,)

=> true=>this is a circle that passes through (,)
and have a center at (,)
so, your answer is .

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Which is the equation of a circle that passes through (2.2) and is centered at (5.6)
Answers:
A. (x-6)^2 + (y-5)^2=25
B. (x-5)^2 + (y-6)^2=5
C. (x+5)^2 + (y+6)^2=25
D. (x-5)^2 + (y-6)^2=25
Thank you for doing this during quarantine :)

DON'T do it the way she tells you to!
And, the points are: (2, 2) and (5, 6)
Equation of a circle: , where: (h, k) are the coordinates of the center
(x, y) is a point on the circumference
r is the radius
We then get: ------ Substituting (2, 2) for (x, y), and (5, 6) for (h, k)

----- Substituting (5, 6) for (h, k), and 25 for r²
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