SOLUTION: Square ABCD is inscribed in a circle. Find the ratio of the area of the square to the area of the circle. Example of a Diagram: https://imgur.com/a/0SgrQoX

Algebra ->  Circles -> SOLUTION: Square ABCD is inscribed in a circle. Find the ratio of the area of the square to the area of the circle. Example of a Diagram: https://imgur.com/a/0SgrQoX      Log On


   



Question 1149200: Square ABCD is inscribed in a circle. Find the ratio of the area of the square to the area of the circle.
Example of a Diagram: https://imgur.com/a/0SgrQoX

Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


Consider the diagonals of the square. Each is a diameter of the circle. Let r be the radius of the circle.

The diagonals of the square divide the square into four 45-45-90 right triangles. The side length of the square (the hypotenuse of one of those right triangles) is sqrt(2) times the length of the radius of the circle.

The area of the square is s%5E2+=+%28r%2Asqrt%282%29%29%5E2+=+2r%5E2

The area of the circle is %28pi%29r%5E2

The ratio of the two areas is

%282r%5E2%29%2F%28%28pi%29r%5E2%29+=+2%2F%28pi%29