SOLUTION: Find the shortest distance from the origin to the graph of the circle with equation given below. x^2−12x+y^2−12y+36=0

Question 1145650: Find the shortest distance from the origin to the graph of the circle with equation given below.

x^2−12x+y^2−12y+36=0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the shortest distance from the origin to the graph of the circle with equation given below.

x^2−12x+y^2−12y+36=0
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Find the center of the circle and its radius.
x^2−12x+y^2−12y+36=0
x^2−12x+y^2−12y = -36
(x-6)^2 + (y-6)^2 = -36 + 36 + 36 = 36
The center is (6,6) and the radius is 6.
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Find the distance d to the center.

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Subtract the radius if d is > radius.
Distance =

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