SOLUTION: Hi there, I was taking the EOC today to test out and this question came up. I have no clue what this is or how to solve it. Please solve and explain what this is and how to do pro

Question 1117232: Hi there,
I was taking the EOC today to test out and this question came up. I have no clue what this is or how to solve it. Please solve and explain what this is and how to do problems like these.
Find the radius of a circle with the equation x^2+y^2-6x-12y=0
Thanks so much, Fawn
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the radius of a circle with the equation x^2+y^2-6x-12y=0
==================
x^2+y^2-6x-12y=0
x^2-6x + y^2-12y = 0
Complete the squares for x & y
x^2-6x+9 + y^2-12y+36 = 0+9+36
x^2-6x+9 + y^2-12y+36 = r^2 = 45
r = sqrt(45) = 3sqrt(5)
==================
PS Tho you didn't ask:
(x-3)^2 + (y-6)^2 = 45 --> the center at (3,6)

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