SOLUTION: A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle I have no idea how to do this question, please send help!

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Question 1107104: A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle
I have no idea how to do this question, please send help!

Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle
===================
Hint:
The radial from the center to the tangent line is perpendicular to the tangent line.

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle.
Here's the graph:



You have the center.  You need the radius, which is the green line.

What you need is the distance formula from a point to a line:

The perpendicular distance from the point (x1,y1)to the line

Ax+By+C=0 is

d = 

Your line is 24x+7y-12 = 0

So you plug in A=24, B=7, C=-12 and (x1,y1) = (2,-3)

Substitute that into the formula for d.  That will be the radius r.

Then substitute (h,k) = (2,-3) and that value of r into



If you have any difficulty, tell me in the note form below and I'll
get back to you by email.

Edwin


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