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the equation of a line 3x-2y=20 what point on the line is equidistant from the points A(1,-1) and B(1,8)
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The point under the question is the intersection point of the given line with the perpendicular bisector to the line segment
connecting the given points A(1,-1) and B(1,8).
Notice that the line connecting these points is VERTICAL line x = 1.
Hence, the perpendicular bisector is the horizontal line y = 3.5 (where 3.5 = ).
The intersection point is that you will obtain after substituting y = 3.5 into the equation of the given line:
3x - 2y = 20 at y = 3.5 becomes 3x - 2*3.5 = 20 ====> 3x = 20+7 = 27 ====> x = = 3.
Hence, the point you are seeking for is (2,3.5).
Thus you can solve this problem MENTALLY, without solving ANY equations.