SOLUTION: find the equation of the axis of symmetry of the parabola f(x)=3x^2+24x+47

Question 109696: find the equation of the axis of symmetry of the parabola f(x)=3x^2+24x+47
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
To find the axis of symmetry, use this formula:

From the equation we can see that a=3 and b=24

Plug in b=24 and a=3

Multiply 2 and 3 to get 6

Reduce

So the axis of symmetry is
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
axis of symmetry of the parabola f(x)=3x^2+24x+47
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Complete the square on the x-terms:
3x^2+24x = y-47
3(x^2+8x+4^2) = y-47+3*4^2
3(x+4)^2 = y+1
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Axis of symmetry: x = -4
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Graph:

Cheers,
Stan H.
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