SOLUTION: he general form of the equation of a circle is x2+y2+2x−6y+1=0.
What are the coordinates of the center of the circle?
Algebra.Com
Question 1079796: he general form of the equation of a circle is x2+y2+2x−6y+1=0.
What are the coordinates of the center of the circle?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
rewrite in form of (x-h)^2+(y-k)^2=r^2
x^2+2x+y^2-6y=-1
complete the square of both
x^2+2x+1+y^2-6y+9=9, after adding 20 to both sides
(x+1)^2+(y-3)^2=3^2
The center is the additive inverse of both constants, so it is at (-1,3) and the radius is 3, the square root of 9.
The center is at (-1, 3)
RELATED QUESTIONS
What is the general form of the equation of a circle with its center at (-2, 1) and... (answered by josgarithmetic)
Find the center and radius of the graph of the circle. The equation of the circle is... (answered by Coyote 10)
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates... (answered by Fombitz)
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for (answered by Alan3354)
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for (answered by ikleyn)
What is the equation of the circle passing through the point (6,5) and centered at... (answered by josgarithmetic)
What are the coordinates of a circle with standard equation x2 + y2 = 49? What is the... (answered by josgarithmetic)
Arrange the circles (represented by their equations in general form) in ascending order... (answered by ikleyn)
find the center and radius of the circle with equation... (answered by Earlsdon)