SOLUTION: Find the equation of the circle that passes through (6,-1); tangent to 4x - 3y

SOLUTION: Find the equation of the circle that passes through (6,-1); tangent to 4x - 3y - 2 = 0 at the points (-1, -2).

Question 1079381: Find the equation of the circle that passes through (6,-1); tangent to 4x - 3y - 2 = 0 at the points (-1, -2).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Label the points:
Find the equation of the circle that passes through A(6,-1); tangent to 4x - 3y - 2 = 0 at the points B(-1,-2).
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Find the perpendicular bisector of AB. The center is on that line.
Find the line perpendicular to the given line thru B. The center is on that line also.
The intersection of the 2 lines is the center.
The distance from the center to A or to B is the radius.
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