SOLUTION: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y

SOLUTION: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y - 12 = 0.

Question 1078546: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y - 12 = 0.
Found 2 solutions by Fombitz, MathLover1:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Find the point of intersection.

Substitute into the second equation,

So,

So then,

Using the point,

Finally,

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

Find the equation of the circle that passes through (,) and with center at the point of intersection of and .

equation of the circle:
and are and coordinates of center, and is radius
use and to find and coordinates of center
...........solve for
............substitute in equation

find

so, and coordinates of center are: and
and equation of your circle (so far) is:

use given point (,) and substitute its and coordinates

->equation of your circle

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