SOLUTION: Write the equation of the line tangent to go (x-4)^2 +y^2 = 25 at x = 9

Question 1063885: Write the equation of the line tangent to go (x-4)^2 +y^2 = 25 at x = 9
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
One of the points on this circle is (9,0), the only point on this circle for which x=0. The circle has center at (4,0), so this radius (of length 5) from center to x=9 on the circle is perpendicular to the desired tangent line at x=9, which means, this tangent line is vertical, having undefined slope.

The line asked for in the question is .

No taking of derivative needed.
RELATED QUESTIONS
The equation of the tangent line to the ellipse x^2/9 +y^2/4=1 at... (answered by stanbon)

Find an equation of the line tangent to the circle (x − 9)^2 + (y − 2)^2 = 25 (answered by Fombitz)

write the equation of the line that is tangent to the circle 25= x^2+y^2 at the point... (answered by ewatrrr)

An equation of the line tangent to the graph of 25=x^2+y^2 at the point (3,4)... (answered by reviewermath)

write the equation of the line tangent to the circle x^2 +y^2=169 at the point... (answered by josgarithmetic)

use implicit differentiation to find an equation of the tangent line to the graph of... (answered by Alan3354)

Find the equation of the tangent to the curve y = (x − 2)√ x 2 + 9 at x =... (answered by josgarithmetic)

find the slope and equation of the tangent line to y=x^4-5x^3+2 at... (answered by josgarithmetic)

what is the equation of the line tangent to the circle x^2+y^2=25 at the point (3,4) ?... (answered by solver91311,eggsarecool)