SOLUTION: A bike is traveling 10 mph. Determine number of revolutions the wheels make in 1 min.
Diameter of wheels: 28 in.
My partial attempt:
Circumference of circle: pi * diamete
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Question 1043271: A bike is traveling 10 mph. Determine number of revolutions the wheels make in 1 min.
Diameter of wheels: 28 in.
My partial attempt:
Circumference of circle: pi * diameter.
3.1416 * 28 = 87.9648 = 88 in. = 7.33 ft.
In 1 revolution the wheels travel 7.33 ft.
7.33 / 5280 = .00138 mi.
How do I proceed?
Non-homework.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A bike is traveling 10 mph. Determine number of revolutions the wheels make in 1 min.
Diameter of wheels: 28 in.
My partial attempt:
Circumference of circle: pi * diameter.
3.1416 * 28 = 87.9648 = 88 in. = 7.33 ft.
In 1 revolution the wheels travel 7.33 ft.
7.33 / 5280 = .00138 mi.
==================
I would first convert 10 mi/hr to ft/minute
10 mi*5280 ft/mile/(1 hr*60 min/hr) = 880 ft/min
---
Times 12 --> 10560 inches/min
---
The bike moves 10560 inches in a minute
Each revolution is 28*pi inches.
# of revs/min = 10560/(28pi) =~ 120 rpm
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