SOLUTION: What is the equation of the circle with center(2,-5) that passes through the point (-2,10)?
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Question 1035889: What is the equation of the circle with center(2,-5) that passes through the point (-2,10)?
Found 2 solutions by richard1234, stanbon:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
(2,-5) -- (-2,10) is a radius of the circle, so the radius r satisfies )^2 + (-5 - 10)^2 = 16 + 225 = 241)
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Then the equation of the circle is ^2 + (y+5)^2 = 241)
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the equation of the circle with center(2,-5)
that passes through the point (-2,10)?
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radius = sqrt[(2--2)^2+(-5-10)^2] = sqrt[16+225] = sqrt(241)
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Equation:
(x-2)^2 + (y+5)^2 = 241
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Cheers,
Stan H.
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