SOLUTION: reduce -3x - 5y + 11 = 0 to normal form and give the distance of the line from the origin.

Question 1014674: reduce -3x - 5y + 11 = 0 to normal form and give the distance of the line from the origin.
Answer by ikleyn(53765) (Show Source): You can put this solution on YOUR website!
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reduce -3x - 5y + 11 = 0 to normal form and give the distance of the line from the origin.
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Normal form equation of this straight line is

3x + 5y = 11.

The distance of the line from the origin (0,0) is 


d =  = .


For details, see the lesson The distance from a point to a straight line in a coordinate plane in this site.

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