SOLUTION: find the equation of circle passing through the points of intersection of the lines x + 3y=0 and 2x- 7y = 0 and whose center is point of intersection lines x + y +1=0 and x-2y +4=0

Question 1010983: find the equation of circle passing through the points of intersection of the lines x + 3y=0 and 2x- 7y = 0 and whose center is point of intersection lines x + y +1=0 and x-2y +4=0
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
find the equation of circle passing through the points of intersection of the lines

--------------find intersection point

substitute in

=>
intersection point is at (,)

and whose center is point of intersection lines

----------------------------subtract

then => =>
so, if the center of the circle is at (,) =(,) and circle passes through (,) , its radius will be the distance between these two points

Solved by pluggable solver: Distance Formula

The first point is (x1,y1). The second point is (x2,y2)

Since the first point is (0, 0), we can say (x1, y1) = (0, 0)
So ,

Since the second point is (-2, 1), we can also say (x2, y2) = (-2, 1)
So ,

Put this all together to get: , , , and

--------------------------------------------------------------------------------------------

Now use the distance formula to find the distance between the two points (0, 0) and (-2, 1)

Plug in , , , and

==========================================================

Answer:

The distance between the two points (0, 0) and (-2, 1) is exactly units

The approximate distance between the two points is about 2.23606797749979 units

So again,

Exact Distance: units

Approximate Distance: units

so, we have , and and the equation of your circle is:

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