SOLUTION: How do I find the standard form of a circle?
The question states
x^2 + Y^2 +6x - 6y - 7 = 0
Algebra.Com
Question 1010222: How do I find the standard form of a circle?
The question states
x^2 + Y^2 +6x - 6y - 7 = 0
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Let us complete the square twice, once in x and once in y and get
x^2 + y^2 + 6x - 6y - 7 = 0
x^2 + 6x + 9 + y^2 - 6y + 9 - 7 = 0 + 9 + 9
(x + 3)^2 + (y - 3)^2 = 25 = 5^2
Center at (-3, 3) and radius 5.
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