.
find standard equation of a circle that has the center on the line 5x-2y= -21 and tangent to both co-ordinate axes.
---------------------------------------------------------------
Notice that the center of this circle lies on the bisector of the first quadrant angle, which is the line y = x.
So, the center is the intersection point of the straight line 5x - 2y = -21 and the straight line y = x.
In other words, to find the center, we should find the point on the line 5x - 2y = -21 with x = y. It has
the coordinates (a,a) such that 5a - 2a = -21. Hence, 3a = -21 and a = -7. Thus the center is (-7,-7).
Then the equation of the circle is
= ,
or
= .
It is not the unique solution.
The other solution can be found if another bisector y = -x of the II-IV quadrants is used.
I don't want to go to this matter, but you can, if you want.