SOLUTION: find standard equation of circle that has centre on the line 5x-2y= -21 and tangent to both co-ordinate axes

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Question 1008377: find standard equation of circle that has centre on the line 5x-2y= -21 and tangent to both co-ordinate axes

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
STRATEGY: The equivalent linear equation, must be an equal distance from x-axis, (x,0) as from y-axis, (0,y), because the point on each axis this equal distance is a point of tangency ON EACH of the axes.

Distance from the center (x, (5/2)x+21/2 ) to x-axis and to y-axis must be equal, because each axis contains a tangency point. Use distance formula.

That is a described strategy, but not the actual solution.

Answer by ikleyn(52799)   (Show Source): You can put this solution on YOUR website!
.
find standard equation of a circle that has the center on the line 5x-2y= -21 and tangent to both co-ordinate axes.
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Notice that the center of this circle lies on the bisector of the first quadrant angle, which is the line y = x.

So, the center is the intersection point of the straight line 5x - 2y = -21 and the straight line y = x.

In other words, to find the center, we should find the point on the line 5x - 2y = -21 with x = y. It has 

the coordinates (a,a) such that 5a - 2a = -21. Hence, 3a = -21 and a = -7. Thus the center is (-7,-7).

Then the equation of the circle is 

 = ,

or

 = .

It is not the unique solution.

The other solution can be found if another bisector y = -x of the II-IV quadrants is used. 
I don't want to go to this matter, but you can, if you want.


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