SOLUTION: X^2+y^2=16 Y=3-x

Question 1005937: X^2+y^2=16
Y=3-x
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
From
x^2+y^2=16
y=3-x
we substitute the second into the first equation and get
x^2 + (3-x)^2 = 16
x^2 + 9 - 6x + x^2 = 16
2x^2 - 6x - 7 = 0
This doesn't factor...you'll have to use the quadratic formula...not sure what you wanted to do here...
It appears to be a circle and a line...
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